WORK
An object is said to make an effort if there is a force that carried out on the object or the object exerts a force causes it to change its position. Work is a major product of the force that causes objects to move with the movement of objects in the direction of the force.
Work (W) can be written in mathematical form, the product of the force (F) and displacement (s).
W = F xs W = Work , the units of joules (J)
F = Force, the units of newtons (N)
s = distance / displacement, units meters (m)
Example
Someone pushed a table in the style of 100 N. Table is shifted as far as 2 m. Calculate the work done man!
Answer:
F = 100 N
s = 2 m
W = .... ?
W = F × s
= 100 N × 2 m
= 200Nm
= 200Joule
An object is said to make an effort if there is a force that carried out on the object or the object exerts a force causes it to change its position. Work is a major product of the force that causes objects to move with the movement of objects in the direction of the force.
Work (W) can be written in mathematical form, the product of the force (F) and displacement (s).
W = F xs W = Work , the units of joules (J)
F = Force, the units of newtons (N)
s = distance / displacement, units meters (m)
Example
Someone pushed a table in the style of 100 N. Table is shifted as far as 2 m. Calculate the work done man!
Answer:
F = 100 N
s = 2 m
W = .... ?
W = F × s
= 100 N × 2 m
= 200Nm
= 200Joule
Component of the force F is in line with the displacement Fx = F cos α,
with α is the wedge angle between the force and the horizontal plane.
example:
a beam in place on the floor slippery drawn style 4 N, at an angle 600 to the horizontal plane. if the beam moves 2m extent, determine the work done!
Given: α = 600
F = 4 N
s = 2 m
Asked: W = ......?
Answer:
W = F. s. cos α
W = 4. 2. cos 600
W = 4. 2. ½
W = 4 joules
Now, how does the amount of work done to move an object to a vertical direction?
Moves objects vertically requires minimal force to overcome the force of gravity equal to the weight of an object. Mathematically force can be written as follows:
F = m.g
Due to the vertical movement of the object with the object height (h), obtained by the work done on the object is as follows.
W = Fs
W = mgh
by: W = usahaJ)
m = mass (kg)
g = acceleration of gravity (N / kg)
h = displacement or height (m)
Example Problem:
An object whose mass is 5 kg lifted vertically to a height of 2 m. If the acceleration of gravity is 10 m/s2 in place, calculate the magnitude of the effort to move the object.
Completion:
Given:
m = 5 kg
h = 2 m
g = 10 m/s2
Asked:
W = ..... ?
Answer:
W = m.g.h
W = (5 kg) (10 m/s2) (2 m)
W = 100 J
Thus, the magnitude of the effort to move the objects to the height of 2 m is 100 joules.
dela,
BalasHapuswhat the dimension of work? please you prove it.
thanks ^^
Assalamu'alaykum..
BalasHapusThanks for the information....
Of corse.. i need this matery now....
Can you please tell me about the frictional force acting on the object?
BalasHapusoke dela, in calculate vertically, is it possible to us meet force using teta?
BalasHapus